3.6 \(\int (a+i a \tan (c+d x)) \, dx\)

Optimal. Leaf size=19 \[ a x-\frac {i a \log (\cos (c+d x))}{d} \]

[Out]

a*x-I*a*ln(cos(d*x+c))/d

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Rubi [A]  time = 0.01, antiderivative size = 19, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3475} \[ a x-\frac {i a \log (\cos (c+d x))}{d} \]

Antiderivative was successfully verified.

[In]

Int[a + I*a*Tan[c + d*x],x]

[Out]

a*x - (I*a*Log[Cos[c + d*x]])/d

Rule 3475

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin {align*} \int (a+i a \tan (c+d x)) \, dx &=a x+(i a) \int \tan (c+d x) \, dx\\ &=a x-\frac {i a \log (\cos (c+d x))}{d}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 19, normalized size = 1.00 \[ a x-\frac {i a \log (\cos (c+d x))}{d} \]

Antiderivative was successfully verified.

[In]

Integrate[a + I*a*Tan[c + d*x],x]

[Out]

a*x - (I*a*Log[Cos[c + d*x]])/d

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fricas [A]  time = 0.42, size = 18, normalized size = 0.95 \[ -\frac {i \, a \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+I*a*tan(d*x+c),x, algorithm="fricas")

[Out]

-I*a*log(e^(2*I*d*x + 2*I*c) + 1)/d

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giac [A]  time = 2.35, size = 18, normalized size = 0.95 \[ a x - \frac {i \, a \log \left ({\left | \cos \left (d x + c\right ) \right |}\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+I*a*tan(d*x+c),x, algorithm="giac")

[Out]

a*x - I*a*log(abs(cos(d*x + c)))/d

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maple [A]  time = 0.02, size = 23, normalized size = 1.21 \[ a x +\frac {i a \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(a+I*a*tan(d*x+c),x)

[Out]

a*x+1/2*I/d*a*ln(1+tan(d*x+c)^2)

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maxima [A]  time = 0.39, size = 17, normalized size = 0.89 \[ a x + \frac {i \, a \log \left (\sec \left (d x + c\right )\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+I*a*tan(d*x+c),x, algorithm="maxima")

[Out]

a*x + I*a*log(sec(d*x + c))/d

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mupad [B]  time = 3.76, size = 17, normalized size = 0.89 \[ \frac {a\,\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(a + a*tan(c + d*x)*1i,x)

[Out]

(a*log(tan(c + d*x) + 1i)*1i)/d

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sympy [A]  time = 0.17, size = 24, normalized size = 1.26 \[ - \frac {i a \log {\left (e^{2 i d x} + e^{- 2 i c} \right )}}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+I*a*tan(d*x+c),x)

[Out]

-I*a*log(exp(2*I*d*x) + exp(-2*I*c))/d

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